1[2](4x-10)=1[3](15x-6)

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Solution for 1[2](4x-10)=1[3](15x-6) equation:


Simplifying
1[2](4x + -10) = 1[3](15x + -6)

Reorder the terms:
1 * 2(-10 + 4x) = 1[3](15x + -6)

Multiply 1 * 2
2(-10 + 4x) = 1[3](15x + -6)
(-10 * 2 + 4x * 2) = 1[3](15x + -6)
(-20 + 8x) = 1[3](15x + -6)

Reorder the terms:
-20 + 8x = 1 * 3(-6 + 15x)

Multiply 1 * 3
-20 + 8x = 3(-6 + 15x)
-20 + 8x = (-6 * 3 + 15x * 3)
-20 + 8x = (-18 + 45x)

Solving
-20 + 8x = -18 + 45x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-45x' to each side of the equation.
-20 + 8x + -45x = -18 + 45x + -45x

Combine like terms: 8x + -45x = -37x
-20 + -37x = -18 + 45x + -45x

Combine like terms: 45x + -45x = 0
-20 + -37x = -18 + 0
-20 + -37x = -18

Add '20' to each side of the equation.
-20 + 20 + -37x = -18 + 20

Combine like terms: -20 + 20 = 0
0 + -37x = -18 + 20
-37x = -18 + 20

Combine like terms: -18 + 20 = 2
-37x = 2

Divide each side by '-37'.
x = -0.05405405405

Simplifying
x = -0.05405405405

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